24t^2-20t=4t

Solution for 24t^2-20t=4t equation:

24t^2-20t=4t

We move all terms to the left:

24t^2-20t-(4t)=0

We add all the numbers together, and all the variables

24t^2-24t=0

a = 24; b = -24; c = 0;
Δ = b2-4ac
Δ = -242-4·24·0
Δ = 576
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{576}=24$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-24)-24}{2*24}=\frac{0}{48}
=0
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-24)+24}{2*24}=\frac{48}{48}
=1
$